[pso] Intrebare (masina big-endian)

[mE]

asta se refera tot la big endian la faptul ca octetii unui uint32_t vor fi pusi in ordine inversa asa ca
daca ai int a = '1gaT'
cand faci un mem dump o sa iti apara Tag1 dar nu are leg cu ordinea elementelor intr-un vector !!!



----- Original Message ----
From: foxX <alex.mihaiuc at gmail.com>
To: Proiectarea Sistemelor de Operare <pso at cursuri.cs.pub.ro>
Sent: Tuesday, September 30, 2008 5:46:41 PM
Subject: Re: [pso] Intrebare (masina big-endian)


poftim http://msdn.microsoft.com/en-us/library/ms796989.aspx
int tag = '1gaT'


2008/9/30 mE <me_registered at yahoo.com>

:) same answer here



----- Original Message ----
From: Alexandru Moşoi <brtzsnr at gmail.com>
To: laurentiu.duca at cs.pub.ro; Proiectarea Sistemelor de Operare <pso at cursuri.cs.pub.ro>
Sent: Tuesday, September 30, 2008 5:26:44 PM
Subject: Re: [pso] Intrebare (masina big-endian)

2008/9/30 Laurentiu-Cristian Duca <laurentiu.duca at mail.cs.pub.ro>:
> Buna ziua,
>
>   Am nevoie de un sfat.
> Pe o masina big-endian,
> char *str="abcd";
> str[0]==(*str) este 'd' // nu este 'a'.

da?
eu stiam ca bigendian se refera la asezarea byteurile intr-un numar
intreg (gen int32_t) si nu intr-un sir. pentru siruri ordinea nu
trebuie sa se schimbe.

daca ai facut ceva de genul:
int a = 45354;
char *str = (int*)&a; s-ar putea sa ai surprize de genul celor de mai
sus, altfel nu vad cum ai obtinut 'd' in loc de 'a'.

oricum, e posibil sa gresesc eu...


-- 
Alexandru Moşoi
http://alexandru.mosoi.googlepages.com

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kthxbai



      
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