la mine e definit ca:<br>word_t* temp = command->params;<br>unde command e un simple_command_t* venit de la parser.<br><br><div class="gmail_quote">On Mon, Mar 30, 2009 at 1:26 PM, Cosmin Ratiu <span dir="ltr"><<a href="mailto:cosminratiu@gmail.com">cosminratiu@gmail.com</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;"><div><div></div><div class="h5"><br><div class="gmail_quote">On Mon, Mar 30, 2009 at 1:13 PM, Dumitru Sorin <span dir="ltr"><<a href="mailto:dumitru.sorin87@gmail.com" target="_blank">dumitru.sorin87@gmail.com</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">
Salut,<br><br>gcc imi da warningul de mai jos la un free la free(temp->string), unde temp = word_t*. Word_t* provine<br>din structura returnata de parser. Cum pot sa scap de warningul asta? <br><br>warning: passing argument 1 of ‘free’ discards qualifiers from pointer target type<br>
</blockquote></div><br></div></div>Este cumva temp const? Mesajul ala zice ca protectia oferita de const este pierduta cand faci cast la non-const (aka pasezi un pointer const la free).<br><font color="#888888"><br>Cosmin.<br>
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